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a theater has 20 rows with 28 seats in the first row, 33 in the second row, 38 in the third row, and so forth. how many seats are in the theater?

Answer :

The number of seats in the theater is 1510.

Here we have to find the number of seats in the theater.

Data given:

Total row = 20

number of seats on the first row = 28

number of seats on the second row = 33

number of seats on the third row = 38

Therefore we get the series as 28, 33, 38......., which is in arithmetic sequence.

The common difference (d) = 5

Here we have to find the sum of the series.

The formula for the sum of n term of the arithmetic sequence:

[tex]S_{n}[/tex] = n/2( 2a + (n-1)d)

    = 20/2 ( 2× 28 + (20 -1) 5)

    = 10 ( 56 + 19×5)

    = 10( 56 + 95)

    = 10 ×151

    = 1510

Therefore the number of seats is 1510.

To know more about the arithmetic sequence refer to the link given below:

https://brainly.com/question/6561461

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