Answer:
0.17M. Option B is correct
Explanations:
The formula calculating the molarity of a solution is given as:
[tex]M=\frac{n}{v}[/tex]
where:
n is the moles of sodium chloride
v is the volume of the solution
Given the following parameters;
The volume of the solution = 3.0L
Determine the moles of NaCl
[tex]\begin{gathered} \text{Moles of NaCl=}\frac{Mass}{Molar\text{ mass}} \\ \text{Moles of NaCl=}\frac{29.2g}{23+35} \\ \text{Moles of NaCl=}\frac{29.2g}{58.5} \\ \text{Moles of NaCl=}0.499\text{moles} \end{gathered}[/tex]
Calculate the required molarity
[tex]\begin{gathered} \text{Molarity}=\frac{0.499\text{moles}}{3.0L} \\ Molarity\approx0.17M \end{gathered}[/tex]
Hence the molarity of the solution is 0.17M
