Answer :
Any time we are working with solutions and its molar concentration we will use the equation:
[tex]C=\frac{n_{\text{solute}}}{V_{\text{solution}}}[/tex]Where C is the concentration, n is the number of moles of the solute and V is the volume of solution.
We can identify such situations when we are working with molarity, molar concentration, solutions with concentration in "M" or "mol/L" units and other cases.
In this case, we can see that we are working with these three quantities:
- We want the volume in mL os a solution, V.
- We have a molar concentration, C, 0.626 M NaOH.
- We have a number of moles of solute we want to get, n, 0.332 mol of NaOH.
So, we have:
[tex]\begin{gathered} V_{\text{solution}}=\; \text{?} \\ C=0.626M=0.626mol/L \\ n_{\text{solute}}=0.332mol \end{gathered}[/tex]So:
[tex]\begin{gathered} C=\frac{n_{\text{solute}}}{V_{\text{solution}}} \\ V_{\text{solution}}=\frac{n_{\text{solute}}}{C}=\frac{0.332mol}{0.626mol/L}=0.530351\ldots L=530.351\ldots mL\approx530mL \end{gathered}[/tex]So, the volume we need is approximately 530 mL.