Answer :
We are given the following polynomial
[tex]5x^2-5[/tex]Let us factor this polynomial.
First of all, notice that you can take 5 common
[tex]5x^2-5=5(x^2-1)[/tex]Now you can apply the difference of squares formula
[tex]a^2-b^2=(a+b)(a-b)[/tex]Where a = x and b = 1
[tex]5\mleft(x^2-1\mright)=5\mleft(x+1\mright)\mleft(x-1\mright)[/tex]Therefore, the factorized polynomial is
[tex]5\mleft(x+1\mright)\mleft(x-1\mright)[/tex]