The length of a leg in a 45-45-90 triangle is 12v2.What is the length of the hypotenuse?1224O 6V224V2

SOLUTION
STEP1: Draw the triangle.
Since two angles of the triangle are equal hence the two legs of the triagle are equal and the lenght are
[tex]12\sqrt[]{2}[/tex]Using the ratio of one of the legs and the hypotenuse side, we have
[tex]\begin{gathered} 1\colon\sqrt[]{2} \\ 12\sqrt[]{2}\colon(12\sqrt[]{2})\sqrt[]{2} \end{gathered}[/tex]Hence the hypothenuse side becomes
[tex]12\sqrt[]{2}\times\sqrt[]{2}=12\times\sqrt[]{4}=12\times2=24[/tex]The lenght of the hypotenuse side is 24