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Prove: segment SD segment PDхO ASDW 2 APWD AASsegment SD 2segment PD corresponding parts of congruent trianglesare congruentASDW_APDW AAS,segment SDsegment PD corresponding parts of congruent trianglesare congruentO ASDW APDWASA,segment SDsegment PD corresponding parts of congruent trianglesare congruentO ASWD – APDW ASA,segment SDsegment PDcorresponding parts of congruent trianglesare congruentws

Prove Segment SD Segment PDхO ASDW 2 APWD AASsegment SD 2segment PD Corresponding Parts Of Congruent Trianglesare CongruentASDWAPDW AASsegment SDsegment PD Corr class=

Answer :

[tex]\begin{gathered} We\text{ have SDW}\approx PDW\text{ by Angle angle side (They share the side DW)} \\ Then\text{ }SD\approx PD\text{ because corresponding parts of }congruent\text{ triangles are congruent} \\ \\ \text{ Thus the answer is}B \end{gathered}[/tex]

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