How much of a 0.250M sucrose solution must be used to prepare 400.0mL of a 0.0310M solution?

1) Preparing a dilution
[tex]C1\cdot V1=C2\cdot V2_{}[/tex]C1: Initial concentration.
V1: Initial volume.
C2: final concentration.
V2: final volume.
2) List known values
C1: 0.250 M sucrose
V1:
C2: 0.0310 M sucrose
V2: 400.0 mL
3) Plug in known values and solve for V2
[tex]0.250\text{ M}\cdot V1=0.0310M\cdot400.0mL[/tex][tex]V1=\frac{0.0310M\cdot400.0mL}{0.250M}=49.6mL[/tex]The solution should be made as follows
Add 49.6mL of 0.250M sucrose to 350.4mL of water to get 400.0mL of 0.0310 M sucrose.