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Construct a polar equation for the conic section with the focus at the originand the following eccentricity and directrix.ConicEccentricityDirectrixparabolae=X =

Construct A Polar Equation For The Conic Section With The Focus At The Originand The Following Eccentricity And DirectrixConicEccentricityDirectrixparabolaeX class=

Answer :

Given:

Here the eccentricity and directrix are 1 and -1/3 respectively of parabola .

Required:

We have to construct a polar equation for the parabola

Explanation:

Formula to construct the polar equation is

[tex]\Gamma=\frac{ep}{1+ecos\emptyset}[/tex][tex]\Gamma=\frac{1*\frac{1}{3}}{1+1cos\emptyset}[/tex][tex]\Gamma=\frac{1}{3+3cos\emptyset}[/tex]

Final answer:

[tex]\Gamma=\frac{1}{3+3cos\emptyset}[/tex]

is the polar equation for given information.

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