Answer :
Answer with explanation: We have to find the Voltage drop in a voltage that has the resistance of 1.02Ohms (1/10G), the formula used is:
[tex]V=IR[/tex]The voltage drop therefore is:
[tex]\begin{gathered} V=(125A)\cdot(1.020\Omega)=127.5V \\ V=127.5\text{Volts} \end{gathered}[/tex]