How many moles of neon occupy a volume of 13.8 L at STP? S

Answer:
0.608 moles are in 13.8L.
Explanation:
At STP conditions, the molar volume of a an ideal gas it is always 22.7L.
So, with a mathematical rule of three we can calculate the moles of neon contained in 13.8L:
[tex]\begin{gathered} 22.7L-1mol \\ 13.8L-x=\frac{13.8L*1mol}{22.7L} \\ x=0.608mol \end{gathered}[/tex]Finally, 0.608 moles are in 13.8L.