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To approximate the length of a marsh, a surveyor walks 425 meters from Pont A to Point B. Then the surveyor turns 65° and walks 300 meters to point C. Approximate the length AC of the marshanswers are not me :)615250

Answer :

Consider the figure.

We have,

[tex]\begin{gathered} AC^2=BC^2+AB^2-2(BC)(AB)cos115\text{ } \\ \text{ =300}^2+425^2-2\times300\times425\times\cos 115 \\ =378392.6567 \\ AC=\sqrt[]{378392.6567}=615 \end{gathered}[/tex]

Thus, the value of ac is 615.

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