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If the hydraulic lift in question 1 needs to lift a car with a weight of 6000 N, what is the surface area of the lifting platform to balance the pressures?Question 1 for reference:1.If a hydraulic lift uses a force of 400 N on a piston of area 0.065 m2, what is the pressure on the piston? (10 points) Approximately 6153.84 Pa

Answer :

Given:

Piston 1 has an area

[tex]A_1=0.065\text{ m}^2[/tex]

and the force applied on this piston is

[tex]F_1=\text{ 400 N}[/tex]

The force on piston 2, which is the weight of the car, is

[tex]F_2=6000\text{ N}[/tex]

Required: The area of piston 2.

Explanation:

The formula that can be obtained by balancing the pressures is

[tex]\begin{gathered} P_1=P_2 \\ \frac{F_1}{A_1}=\frac{F_2}{A_2} \\ A_2=\frac{F_2A_1}{F_1} \end{gathered}[/tex]

On substituting the values, the area of the second piston will be

[tex]\begin{gathered} A_2=\frac{6000\times0.065}{400} \\ =0.975\text{ m}^2 \end{gathered}[/tex]

Final Answer: The area of the piston lifting the car is 0.975 meter-squared.

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