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Part (b)A cassette recorder uses a plug-in transformer to convert 120 V to 12.0 V, with a maximum current output of 355 mA. (b) What is the power input (in W)?

Answer :

Given

The input voltage, V=120 V

The output voltage, V'=12.0 V

Current output is I'=355 mA

To find

(b) What is the power input (in W)?

Explanation

We know,

[tex]\begin{gathered} VI=V^{\prime}I^{\prime} \\ \Rightarrow120I=12\times355\times10^{-3} \\ \Rightarrow I=0.0355\text{ A} \end{gathered}[/tex]

The power input is

[tex]\begin{gathered} P=IV \\ \Rightarrow P=120\times0.0355 \\ \Rightarrow P=4.26\text{ W} \end{gathered}[/tex]

Conclusion

The power input is 4.26 W