Answer :
Let the number of dimes = x
And the number of nickels = y
There are 8 more dimes than nickels.
So, x = y + 8
The jar of nickels and dimes contains $5.45
So, the total amount of money = 545 cents
dime = 10 cents
nickel = 5 cents
so, 10x + 5y = 545
so, we have the following system of equations:
[tex]\begin{gathered} x=y+8\rightarrow(1) \\ 10x+5y=545\rightarrow(2) \end{gathered}[/tex]Substitute with x from equation (1) into equation (2) then solve for y
[tex]\begin{gathered} 10(y+8)+5y=545 \\ 10y+80+5y=545 \\ 15y=545-80 \\ 15y=465 \\ \\ y=\frac{465}{15}=31 \\ x=31+8=39 \end{gathered}[/tex]So, the number of dimes = 39
The number of nickels = 31