Answer :
The probability at least one will have a defect is 1 - the probability no one will have a defect.
The probability no one will have a defect is:
[tex]\begin{gathered} \frac{90}{100}\cdot\frac{90}{100}\cdot\frac{90}{100}\cdot\frac{90}{100}\cdot\frac{90}{100}\cdot\frac{90}{100}\cdot\frac{90}{100}\cdot\frac{90}{100} \\ =(0.9)^8 \\ =0.4305 \end{gathered}[/tex]So, the probability (P) that at least one will have a defect:
P = 1 - 0.4305
P = 0.5695 = 56.95%
Answer:
P = 0.5695 = 56.95%.