Answer :
[tex]\begin{gathered} W=70J \\ F=15N \\ d=\text{?} \\ W=Fd \\ \text{Solving d } \\ d=\frac{W}{F}=\frac{70J}{15N}=4.67m \\ d=4.67\text{ m} \\ The\text{ distance He moved the box is 4.67m} \\ \\ \text{Question 2)} \\ False,\text{ in p}\operatorname{erf}ect\text{ conditions the efficiency will be 100\% not greater } \end{gathered}[/tex]