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8. Find the slope of the line containing the points (-3,-3) and (-2,1).

Answer :

Slope is:

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

At the point (-3,-3) and (-2,1).

so:

[tex]\begin{gathered} x_1=-3 \\ y_1=-3 \\ x_2=-2 \\ y_2=1 \end{gathered}[/tex]

so the slope is:

[tex]\begin{gathered} m=\frac{y_2-y_1}{x_2-x_1} \\ m=\frac{1-(-3)}{(-2)-(-3)} \\ m=\frac{1+3}{-2+3} \\ m=\frac{4}{1} \\ m=4 \end{gathered}[/tex]

slope of the line is 4.

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