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**Given p(x) = 23=23 - 6x^2 - 5x - 14, determinewhether (x - 7) is a factor of p(x).

Given Px 2323 6x2 5x 14 Determinewhether X 7 Is A Factor Of Px class=

Answer :

Given:

[tex]p(x)=x^3-6x^2-5x-14[/tex]

Factor of (x-7) is:

[tex]\begin{gathered} =\frac{p(x)}{x-7} \\ =\frac{x^3-6x^2-5x-14}{x-7} \end{gathered}[/tex]

so factor of (x-7) is:

[tex]\begin{gathered} p(x)=x^3-6x^2-5x-14 \\ =(x-7)(x^2+x+2) \end{gathered}[/tex]

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