Given the quadratic equation:
[tex]4x^2+8x+4[/tex]
Factorizing the common factor:
[tex]4(x^2+2x+1)[/tex]
But we know that:
[tex](x+1)^2=x^2+2x+1[/tex]
Now, using this identity:
[tex]4x^2+8x+4=4(x+1)^2[/tex]
We conclude that the factoring pattern is a perfect square trinomial
