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You need a 5% alcohol solution. On hand, you have a 60 mL of a 60% alcohol mixture. How much pure waterwill you need to add to obtain the desired solution?

You Need A 5 Alcohol Solution On Hand You Have A 60 ML Of A 60 Alcohol Mixture How Much Pure Waterwill You Need To Add To Obtain The Desired Solution class=

Answer :

It is given that a 5% alchohol solution needs to be prepared.

It is given that 60ml of 60% pure alchohol solution.

So let x ml of pure water be added, so it follows:

[tex]60(\frac{60}{100})+x(\frac{0}{100})=(60+x)\frac{5}{100}[/tex]

Solve for x to get:

[tex]\begin{gathered} 36=\frac{\mleft(60+x\mright)}{20} \\ 720=60+x \\ x=660 \end{gathered}[/tex]

660 ml of pure water needs to be added to get the 5% solution.

b) You will need 660ml of pure water to obtain 720ml of the desired 5% solution.

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