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Answered

In a circle with radius 0.9, an angle intercepts an arc of length 3.6. Find the angle inradians to the nearest tenth.

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SOLUTION

Given the question on the question tab;

[tex]\begin{gathered} radius\text{ r=0.9} \\ angle\text{ }\theta=? \\ Length\text{ of arc=3.6} \end{gathered}[/tex][tex]\begin{gathered} Length\text{ of arc =}\theta r \\ 3.6=0.9\theta \\ \theta=\frac{3.6}{0.9} \\ \theta=4.0 \end{gathered}[/tex]

The angle is 4.0

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