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Padma is covering the top of her square pyramid with gold foil. If there is no overlap, how much foil will she need?Round to the nearest cm2

Padma Is Covering The Top Of Her Square Pyramid With Gold Foil If There Is No Overlap How Much Foil Will She NeedRound To The Nearest Cm2 class=

Answer :

Answer: She will need 1239 cm^3 of foil

Explanation:

Surface area of square pyramid = base area of square + area of 4 triangular faces

Area of square base = l^2

where

l is the length of each side of the square base

From the information given,

l = 8

Area of square base = 8^2 = 64

Area of each triangular face = 1/2 x base x height

We would find the height of each face by applying Pythagorean theorem to the right triangle formed below. It is ex[ressed as

hypotenuse^2 = one leg^2 + other leg^2

hypotenuse = 10

one leg = 4

other leg = h

4^2 + h^2 = 10^2

36 + h^2 = 100

h^2 = 100 - 36 = 64

h = √64

h = 8

base = 8

Area of 4 triangular faces 4 x 1/2 x 8 x 8 = 128

Surface area of square base pyramid = 128 + 64 = 192 in^2

We would convert 192 in^2 cm^2

Recall,

1 inch^2 = 6,4516 cm^2

192 inch^2 = 192 x 6.4516

= 1239 cm^2

She will need 1239 cm^3 of foil

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