Answer :
SOLUTION:
Using a normal distribution table, we find that;
a. The area to the left of z = 1.62 is;
[tex]P(z<1.62)=0.9474[/tex]b. The area between z = -1.53 and z = -1.82, this is;
[tex]P(-1.82SOLUTION:
Using a normal distribution table, we find that;
a. The area to the left of z = 1.62 is;
[tex]P(z<1.62)=0.9474[/tex]b. The area between z = -1.53 and z = -1.82, this is;
[tex]P(-1.82