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Evaluate a2 + 2b – 3c for a= -2, b = 5 and c = 10

Answer :

[tex]a^2+2b-3c[/tex]

a= -2, b=5 and c=10

[tex]\begin{gathered} we\text{ just ne}ed\text{ to substitute } \\ (-2)^2+2(5)-\text{ 3}(10) \\ 4+10-30 \\ =14-30 \\ =-16 \end{gathered}[/tex]

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