Answer :
Let the polynomial function be f(x)
Given that f(x) has two zeroes -3 and 4i
Then, f(x) can be written as
f(x)=[x-(-3)](x-4i)
On multiplying,
f(x)=(x+3)(x-4i)
=x^2+(3-4i)x-12i
The leading coefficient is 1 and the roots are -3 and 4i
Let the polynomial function be f(x)
Given that f(x) has two zeroes -3 and 4i
Then, f(x) can be written as
f(x)=[x-(-3)](x-4i)
On multiplying,
f(x)=(x+3)(x-4i)
=x^2+(3-4i)x-12i
The leading coefficient is 1 and the roots are -3 and 4i