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If 30 j of magnetic potential energy is stored in a 6. 0-h inductor, what is the current in the inductor?

Answer :

Current in the inductor, I = 100A

Given,

Magnetic potential energy stored, U= 30 joule

Inductance, L = 6.0 H

Therefore, current in the inductor, [tex]I^{2}[/tex]= (2×30×10^3) ÷ 6

                                                           = 2×5×10^3

                                                           = 10×10^3

                                                   [tex]I^{2}[/tex]       = 10000

                                                   I        = √10000

                                                  I        = 100A

Concept:-

  • As a result of the magnetic forces that magnets exert on one another, magnetic potential energy is the energy that is stored in a system of magnets.
  • Magnetic potential energy stored in an inductor, U = 1/2 (L[tex]I^{2}[/tex])
  • L is the inductance of the inductor.
  • I is the current flowing through the inductor.

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