The value of x in the triangle is (a) 22
How to solve for x?
The complete question is in the attached image.
From the attached image of the triangle, we have:
[tex]\sin(45) = \frac{x}{22\sqrt 2}[/tex]
Evaluate sin(45)
[tex]\frac{1}{\sqrt 2} = \frac{x}{22\sqrt 2}[/tex]
Solve for x
[tex]x = \frac{22\sqrt 2}{\sqrt 2}[/tex]
Divide
x = 22
Hence, the value of x is (a) 22
Read more about special triangles at:
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