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Answered

2. A generator coil has 25 turns of wire and a cross-sectional area of 36 cm2.
The maximum emf developed in the generator is 2.8 V at 60 Hz. What is
the strength of the magnetic field in which the coil rotates?

Answer :

Angular speed

  • 2πf

f is frequency

  • 2(3.14)(60)
  • 376.8

Area=36cm²=0.0036m²

Now

[tex]\\ \rm\Rrightarrow emf=nAB\omega[/tex]

[tex]\\ \rm\Rrightarrow 2.8=25\times 36\times 10^{-4}\times 376.8B[/tex]

[tex]\\ \rm\Rrightarrow 2.8=33.84B[/tex]

[tex]\\ \rm\Rrightarrow B=0.0827T[/tex]

[tex]\\ \rm\Rrightarrow 8.3\times 10^{-3}T[/tex]

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