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2S+3O2=2SO3. If 4moles of sulfur reacts with 9. 5 moles of oxygen, how many moles of oxygen would remain after the reaction?

Answer :

MEDUNNO13IN

Answer: 3.5 moles

Explanation:

For every 2 moles of sulfur consumed, there are 3 moles of oxygen consumed.

This means that sulfur is the limiting reactant, meaning that 2(3)=6 moles of oxygen will be consumed.

Thus, 9.5-6=3.5 moles of oxygen will remain.

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