Answer:
x²-7x+10=0
x²-5x-2x+10=0
x(x-5)-2(x-5)=0
(x-2)(x-5)=0 ANS!
Step-by-step explanation:
First we will multiply x² into 10, the answer will be 10x². Now, take L.C.M of 10, the L.C.M will be 5x2 or 2x5. Now we will make sure that:
2x x 5x=10x² while 5x+2x=7x. Now, we know that 7x is in negative so, we will change the signs and it will become x²-5x-2x+10=0. Now take common:
x(x-5)-2(x-5)=0. Now, write the common taken numbers first and then the other brackets in last i.e: (x-2)(x-5)=0
