Answer:
P(caramel) = 3/10
P(raspberry) = 1/3
Step-by-step explanation:
Given:
- Caramel chocolates = 3
- Raspberry chocolates = 3
- Fudge chocolates = 4
⇒ Total chocolates = 3 + 3 + 4 = 10
[tex]\sf Probability \ of \ an \ event \ occurring = \dfrac{Number \ of \ ways \ it \ can \ occur}{Total \ number \ of \ possible \ outcomes}[/tex]
[tex]\sf \implies P(picking \ caramel \ chocolate) = \dfrac{3}{10}[/tex]
If the picked caramel chocolate is NOT replaced then:
- Caramel chocolates = 3 - 1 = 2
- Raspberry chocolates = 3
- Fudge chocolates = 4
- Total chocolates = 10 - 1 = 9
[tex]\sf \implies P(picking \ raspberry \ chocolate) = \dfrac39=\dfrac13[/tex]
