👤
ARIANNASMITH006IN
Answered

What are the solution(s) for the quadratic equation?

Y=x^2-2x+1

Answer :

[tex]\\ \rm\rightarrowtail x^2-2x+1=0[/tex]

[tex]\\ \rm\rightarrowtail x^2-x-x+1=0[/tex]

[tex]\\ \rm\rightarrowtail x(x-1)-1(x-1)=0[/tex]

[tex]\\ \rm\rightarrowtail (x-1)(x-1)=0[/tex]

[tex]\\ \rm\rightarrowtail x=1[/tex]

In Trainings: Other Questions