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Answered

Four of the interior angles of a hexagon are 128º. The other two angles are equal.
How large are the other two angles?

Answer :

INDRAWBOYIN

hexagon = 6 (n)

total angle = 180 (n - 2)

total angle = 180(6-2) =720

4 angles = 4 x 128 = 512

the other two angle = 720 - 512 =208

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