∠A = 180° - (63°+101°)=16°
sine's rule
[tex]\tt \dfrac{AB}{sin~C}=\dfrac{BC}{sin~A}\\\\\dfrac{AB}{sin~63}=\dfrac{9}{sin~16}\\\\AB=29.09[/tex]
Answer:
AB = 29
Step-by-step explanation:
Law of Sines:
[tex]\frac{9}{sin 16}[/tex] = [tex]\frac{x}{sin 63}[/tex]
cross-multiply:
x·sin(16°) = 9·sin(63°)
x = [tex]\frac{9sin63}{sin16}[/tex]
x = 29
