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Mathematics

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Answer :

АНОНИМIN АНОНИМIN

Answer:

sec²-2scθ+tanθ+tan²θ=1-sinθ/1+sinθ

sec²-2scθ+tanθ+tan²θ

= 1+sin²θ-2sinθ/cos²θ

=-1+sinθ/1+sinθ

=1-sinθ/sinθ+1

1-sinθ/sinθ+1=-1+sinθ/1+sinθ True

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