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3. A ball of mass 2.0 kg is attached to a vertical spring. The spring constant is 196 N/m. What is the period if it were to be in SHM?
-0.063
-0.63 5
-6.3 s
-63 s
PLEASEHELPME

Answer :

ASUWAFOHJAMESIN

The period of the ball in simple harmonic motion is 0.634 s.

What is period?

Period can be defined as the time ( in seconds) taken for a body to complete one oscillation.

To calculate the period of the ball in SHM, we use the formula below.

Formula:

  • T = 2π√(m/k)............... Equation 1

Where:

  • T = Period of the ball
  • m = mass of the ball
  • k = spring constant
  • π  = pie

From the question,

Given:

  • m = 2 kg
  • k = 196 N/m
  • π = 3.14

Substitute these values into equation 1

  • T = 2(3.14)√(2/196)
  • T = 6.28√(0.010204)
  • T = 0.634 s

Hence, The period of the ball in simple harmonic motion is 0.634 s.  

Learn more about period here: https://brainly.com/question/21924087

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