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Given two consecutive integers whose sum is 45, find the smaller of the two integers.

Answer :

SQDANCEFANIN

Answer:

  22

Step-by-step explanation:

Let x represent the smaller integer. Then x+1 is the larger. Their sum is ...

  x +(x+1) = 45

  2x = 44 . . . . . subtract 1

  x = 22 . . . . . divide by 2

The smaller of the two integers is 22.

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