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An athlete throws a javelin, a long metal spear, at a track and field competition. The javelin's height in feet, h, as a function of the number of seconds since it was thrown, t, is modelled by the equation h (t)=-16t2 + 128t. What is the height of the javelin after 5 seconds? A) O feet B) 8 feet C) 240 feet D) 480 feet​

Answer :

CLARCH19IN

Answer:

C)  240 feet

Step-by-step explanation:

't' represents seconds so we need to find:

h(5) = -16(5²) + 128(5)

h(5) = -16(25) + 640

h(5) = -400 + 640

h(5) = 240 feet

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