Answer :
A. The period of its rotation is 5 s
B. The frequency of its rotation is 0.2 Hz
Data obtained from the question
- Number of rotation (n) = 10
- Time (t) = 50 s
A. Determination of the period
- Number of rotation (n) = 10
- Time (t) = 50 s
- Period (T) =?
The period of the rotation can be obtained as follow:
T = t/n
T = 50 / 10
T = 5 s
B. Determination of the frequency
- Period (T) = 5 s
- Frequency (f) =?
The frequency of the rotation can be obtained as follow:
f = 1/T
f = 1/5
f = 0.2 Hz
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