The net ionic equation for the reaction between Li₃PO₄ and Ba(NO₃)₂ is:
In solution, Li₃PO₄ and Ba(NO₃)₂ will dissociate as follow:
Li₃PO₄ (aq) —> 3Li⁺(aq) + PO₄³¯(aq)
Ba(NO₃)₂ (aq) —> Ba²⁺(aq) + 2NO₃¯(aq)
The reaction will proceed as follow:
Li₃PO₄(aq) + Ba(NO₃)₂(aq) —>
3Li⁺(aq) + PO₄³¯(aq) + Ba²⁺(aq) + 2NO₃¯(aq) —> 3Li⁺(aq) + 2NO₃¯(aq) + Ba₃(PO₄)₂(s)
Cancel the spectator ions (i.e Li⁺ and NO₃¯)
PO₄³¯(aq) + Ba²⁺(aq) —> Ba₃(PO₄)₂(s)
Balacing the equation above, we have:
2PO₄³¯(aq) + 3Ba²⁺(aq) —> Ba₃(PO₄)₂(s)
Therefore, the net ionic equation for the reaction between Li₃PO₄ and Ba(NO₃)₂ is:
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