Answer :
Answer:
[tex]\frac{1+sinA}{cosA}=\frac{\frac{cotA}{2}-1 }{\frac{cotA}{2}+1 } \\\\<=>(1+sinA)(\frac{cotA}{2}+1)=(\frac{cotA}{2}-1)cosA\\\\<=>\frac{cotA}{2}+\frac{cosA}{2}+1+sinA=\frac{cosA.cotA}{2}-cosA\\\\[/tex]
=> 2 sides cant be equal
Step-by-step explanation: