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Mathematics

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Answer :

JIMRGRANT1IN JIMRGRANT1IN

Answer:

5th option

Step-by-step explanation:

The secant- tangent angle DCB is half the difference of the intercepted arcs, that is

∠ 1 = [tex]\frac{1}{2}[/tex] ( AD - BD)

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(sec(t)-cos(t))/sin(t)

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(sec(t)-cos(t))/sin(t)

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