Answer :
Answer:
L(f(t)) = [tex]\frac{5s - 60\sqrt{3} }{s^2 + 144}[/tex]
Step-by-step explanation:
f ( t ) = 10 cos ( 12t + 60°) u(t)
attached below is a detailed solution of the given problem
L(f(t)) = [tex]\frac{5s - 60\sqrt{3} }{s^2 + 144}[/tex]

Answer:
L(f(t)) = [tex]\frac{5s - 60\sqrt{3} }{s^2 + 144}[/tex]
Step-by-step explanation:
f ( t ) = 10 cos ( 12t + 60°) u(t)
attached below is a detailed solution of the given problem
L(f(t)) = [tex]\frac{5s - 60\sqrt{3} }{s^2 + 144}[/tex]