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.. The solution of which quadratic Inequality is shown on the number line?
O (3+6) (3 – 4) <0
O (2-6) (2 - 4) > 0
O (30 – 6)(+4) <0.
O (30 – 6) (x – 4) <0

The Solution Of Which Quadratic Inequality Is Shown On The Number Line O 36 3 4 Lt0 O 26 2 4 Gt 0 O 30 64 Lt0 O 30 6 X 4 Lt0 class=

Answer :

Answer:  Choice C

Explanation:

If you graphed (x-6)(x+4) on the xy plane, then you'll see a parabola forming. This parabola has roots at x = -4 and x = 6. Between these roots, the curve is below the x axis. This visually shows that (x-6)(x+4) is negative when -4 < x < 6.

Furthermore, we can say that (x-6)(x+4) is negative or zero when [tex]-4 \le x \le 6[/tex] which corresponds directly to the number line graph your teacher gave you. The endpoints being closed circles mean "include this as part of the shaded solution set".

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