Answer:
206°C
Explanation:
To solve this question we must use the combined gas law:
PV = nRT
Where P is pressure in atm, V is volume in liters, T absolute temperature, n are moles of gas, and R gas constant.
Pressure:
450kPa * (1atm / 101.325kPa) = 4.441atm
Volume:
658mL = 0.658L
Moles -Molar mass Ne: 20.1797g/mol-
1.50g * (1mol / 20.1797g) = 0.07433 moles
R: 0.082atmL/molK
Replacing to solve T:
T = PV/nR = 4.441atm*0.658L / 0.07433 moles*0.082atmL/molK =
T = 479K
In °C:
479K -273 =
206°C
