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Answered

Find the perimeter of a rectangle with a length that is fifteen more than ten times the width

Answer :

SHREYA27032006IN

Step-by-step explanation:

let the width be x

length= 10x+ 15

perimeter = 2(l+b)

= 2(10x+ 15 + x)

2(11x+15)

=22x+30

NINJA855IN

Step-by-step explanation:

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