Answer:
[tex]V_1=0.0714L[/tex]
Explanation:
Hello there!
In this case, since we need to dilute the 1.75-M HCl, and the total number of moles remain unchanged, we can write:
[tex]n_1=n_2[/tex]
And in terms of volume and concentration:
[tex]C_1V_1=C_2V_2[/tex]
Thus, we can solve for the volume of the concentrated HCl as shown below:
[tex]V_1=\frac{C_2V_2}{C_1}[/tex]
Therefore, we plug in the data to get:
[tex]V_1=\frac{0.250M*0.500L}{1.75 M}\\\\V_1=0.0714L[/tex]
Best regards!
