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Chemistry

Answered

Calculate the molarity of 32.5 g of MgS in 935 mL of solution.

Answer :

ZENABHUSSAIN4IN ZENABHUSSAIN4IN

Molarity = mol / liter = 0.569 / 0.841 = 0.677

You convert 841 mL of solution to 0.841 L
You convert 32.1g of MgS to mol by dividing by molar mass of MgS (which is 56.4g)

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