Answer :
substitute x for 2
5(2)^5-3(2)^4-17(2)^3-4(2)^2+10(2)+21
do the exponents
5(32)-3(16)-17(8)-4(4)+10(2)+21
simplify
160-48-136-16+20+21
1
f(2)=1
5(2)^5-3(2)^4-17(2)^3-4(2)^2+10(2)+21
do the exponents
5(32)-3(16)-17(8)-4(4)+10(2)+21
simplify
160-48-136-16+20+21
1
f(2)=1
Answer: f(2)=1
Step-by-step explanation:
This is a function-related problem. In order to solve f(2), you need to substitute the value into the original function.
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f(x)=5x⁵-3x⁴- 17x³-4x²+10x+21
f(2)=5(2)⁵-3(2)⁴- 17(2)³-4(2)²+10(2)+21
f(2)=160-48-136-16+20+21
f(2)=1
Hope this helps!!
Please let me know if you have any questions