Answer:
i belive there is no solution
Step-by-step explanation:
210° , 270°
6+6sinθ = 4cos²θ = 4 (1-sin²θ) = 4 - 4 sin²θ
4 sin²θ + 6 sinθ + 2 = 2(2 sin²θ + 3 sinθ + 1) = 0
2* (sinθ + 1) (2sinθ + 1) = 0
sinθ = -1 or sinθ = -1/2
θ = 270° or θ = 210°
